1869 Minnesota gubernatorial election

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
1869 Minnesota gubernatorial election
← 1867 November 2, 1869 1871 →
  Horace Austin (1873).jpg No image.svg
Nominee Horace Austin George L. Otis
Party Republican Democratic
Popular vote 27,348 25,401
Percentage 50.17% 46.60%

MNGubernatorial1869.svg
County Results:


Austin:      40-50%      50-60%      60-70%      70-80%      80-90%      90-100%
Otis:      50–60%      60–70%      70-80%      80-90%      90-100%
Unknown/No Vote:      



Governor before election

William Rainey Marshall
Republican

Elected Governor

Horace Austin
Republican

The 1869 Minnesota gubernatorial election was held on November 2, 1869 to elect the governor of Minnesota.

Results[edit]

Minnesota gubernatorial election, 1869[1][2]
Party Candidate Votes %
Republican Horace Austin 27,348 50.17
Democratic George L. Otis 25,401 46.60
Prohibition Daniel Cobb 1,764 3.24
Total votes 54,513 100
Republican hold

References[edit]

  1. ^ "Our Campaigns - MN Governor Race - Nov 02, 1869". Retrieved May 7, 2016.
  2. ^ "Minnesota Legislative Manual (Blue Book) - Chapter 10 Minnesota Elections" (PDF). Office of the Minnesota Secretary of State. 2015-04-01. Retrieved 2016-05-07.