In the study of geometric algebras, a blade is a generalization of the concept of scalars and vectors to include simple bivectors, trivectors, etc. Specifically, a k-blade is any object that can be expressed as the exterior product (informally wedge product) of k vectors, and is of grade k.

In detail:[1]

• A 0-blade is a scalar.
• A 1-blade is a vector. Every vector is simple.
• A 2-blade is a simple bivector. Linear combinations of 2-blades also are bivectors, but need not be simple, and are hence not necessarily 2-blades. A 2-blade may be expressed as the wedge product of two vectors a and b:
${\displaystyle a\wedge b.}$
• A 3-blade is a simple trivector, that is, it may be expressed as the wedge product of three vectors a, b, and c:
${\displaystyle a\wedge b\wedge c.}$
• In a space of dimension n, a blade of grade n − 1 is called a pseudovector[2] or an antivector.[3]
• The highest grade element in a space is called a pseudoscalar, and in a space of dimension n is an n-blade.[4]
• In a space of dimension n, there are k(nk) + 1 dimensions of freedom in choosing a k-blade, of which one dimension is an overall scaling multiplier.[5]

For an n-dimensional space, there are blades of all grades from 0 to n inclusive. A vector subspace of finite dimension k may be represented by the k-blade formed as a wedge product of all the elements of a basis for that subspace.[6]

## Examples

For example, in 2-dimensional space scalars are described as 0-blades, vectors are 1-blades, and area elements are 2-blades known as pseudoscalars, in that they are elements of a one-dimensional space distinct from regular scalars.

In three-dimensional space, 0-blades are again scalars and 1-blades are three-dimensional vectors, and 2-blades are oriented area elements. 3-blades represent volume elements and in three-dimensional space; these are scalar-like—i.e., 3-blades in three-dimensions form a one-dimensional vector space.

5. ^ For Grassmannians (including the result about dimension) a good book is: Griffiths, Phillip; Harris, Joseph (1994), Principles of algebraic geometry, Wiley Classics Library, New York: John Wiley & Sons, ISBN 978-0-471-05059-9, MR 1288523. The proof of the dimensionality is actually straightforward. Take k vectors and wedge them together ${\displaystyle v_{1}\wedge \cdots \wedge v_{k}}$ and perform elementary column operations on these (factoring the pivots out) until the top k × k block are elementary basis vectors of ${\displaystyle \mathbb {F} ^{k}}$. The wedge product is then parametrized by the product of the pivots and the lower k × (nk) block.