1824 United States presidential election in Alabama
|Elections in Alabama|
The 1824 United States presidential election in Alabama took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Alabama voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Alabama by a margin of 51.52%.
|United States presidential election in Alabama, 1824|
|Democratic-Republican||John Quincy Adams||2,422||17.80%||0|
|Democratic-Republican||William H. Crawford||1,656||12.17%||0|
- "1824 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 27 February 2013.
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