1824 United States presidential election in Georgia

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United States presidential election in Georgia, 1824
Flag of the State of Georgia (non-official).svg
← 1820 October 26 – December 2, 1824 1828 →
  WilliamHCrawford.jpg
Nominee William H. Crawford
Party Democratic-Republican
Home state Georgia
Running mate Nathaniel Macon
Electoral vote 9

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in Georgia took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Georgia cast nine electoral votes for native William H. Crawford.

Results[edit]

United States presidential election in Georgia, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican William H. Crawford 9
Democratic-Republican John Quincy Adams 0
Democratic-Republican Henry Clay 0
Democratic-Republican Andrew Jackson 0
Totals 9

References[edit]

  1. ^ "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved 28 February 2013.