1836 United States presidential election in Kentucky

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United States presidential election in Kentucky, 1836

← 1832 November 3 – December 7, 1836 1840 →
  William Henry Harrison by James Reid Lambdin, 1835 crop.jpg Van Buren.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 15 0
Popular vote 36,861 33,229
Percentage 52.59% 47.41%

The 1836 United States presidential election in Kentucky took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results[edit]

United States presidential election in Kentucky, 1836[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 36,861 52.59% 15
Democratic Martin Van Buren 33,229 47.41% 0
Totals 70,090 100.0% 15

References[edit]

  1. ^ "1836 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 4 August 2012.