1836 United States presidential election in Maryland

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United States presidential election in Maryland, 1836

← 1832 November 3 – December 7, 1836 1840 →
  William Henry Harrison by James Reid Lambdin, 1835 crop.jpg Van Buren.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 10 0
Popular vote 25,852 22,267
Percentage 53.73% 46.27%

The 1836 United States presidential election in Maryland took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Maryland by a margin of 7.46%.

Results[edit]

United States presidential election in Maryland, 1836[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 25,852 53.73% 10
Democratic Martin Van Buren 22,267 46.27% 0
Totals 48,119 100.0% 10

References[edit]

  1. ^ "1836 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 4 August 2012.