1836 United States presidential election in Tennessee

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United States presidential election in Tennessee, 1836

← 1832 November 3 – December 7, 1836 1840 →
  HLWhite.jpg Van Buren.jpg
Nominee Hugh Lawson White Martin Van Buren
Party Whig Democratic
Home state Tennessee New York
Running mate John Tyler Richard Mentor Johnson
Electoral vote 15 0
Popular vote 36,027 26,170
Percentage 57.92% 42.08%

The 1836 United States presidential election in Tennessee took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose fifteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for Whig candidate Hugh White, a Senator for Tennessee, over Democratic candidate Martin Van Buren. White won Tennessee by a margin of 15.84%.

Results[edit]

United States presidential election in Tennessee, 1836[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Hugh White of Tennessee John Tyler of Virginia 36,027 57.92% 15 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 26,170 42.08% 0 0.00%
Total 62,197 100.00% 15 100.00%

References[edit]

  1. ^ "1836 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 23 December 2013.