1840 United States presidential election in Connecticut

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1840 United States presidential election in Connecticut

← 1836 October 30 - December 2, 1840 1844 →
  Harrison crop.jpg Van Buren.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 8 0
Popular vote 31,598 25,281
Percentage 55.55% 44.45%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Connecticut took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Connecticut by a margin of 11.1%.

Results[edit]

1840 United States presidential election in Connecticut[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 31,598 55.55% 8 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 25,281 44.45% 0 0.00%
Total 56,879 100.00% 8 100.00%

References[edit]

  1. ^ "1840 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 23 December 2013.