1840 United States presidential election in Indiana
|Elections in Indiana|
The 1840 United States presidential election in Indiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
|United States presidential election in Indiana, 1840|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Whig||William Henry Harrison of Ohio||John Tyler of Virginia||65,302||55.86%||9||100.00%|
|Democratic||Martin Van Buren of New York||Richard M. Johnson of Kentucky||51,604||44.14%||0||0.00%|
- "1840 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.
|This Indiana elections-related article is a stub. You can help Wikipedia by expanding it.|