1840 United States presidential election in New Jersey

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United States presidential election in New Jersey, 1840

← 1836 October 30 - December 2, 1840 1844 →
  Harrison crop.jpg Van Buren.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 8 0
Popular vote 33,351 31,034
Percentage 51.74% 48.15%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in New Jersey took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New Jersey by a margin of 3.59%.

Results[edit]

United States presidential election in New Jersey, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 33,351 51.74% 8 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 31,034 48.15% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 69 0.11% 0 0.00%
Total 64,454 100.00% 8 100.00%

References[edit]

  1. ^ "1840 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 23 December 2013.