1852 United States presidential election in Wisconsin

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United States presidential election, 1852

← 1848 November 2, 1852 1856 →
  Mathew Brady - Franklin Pierce crop.jpg Winfield Scott by Fredricks, 1862 crop.jpg JP-Hale crop.jpg
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote 5 0 0
Popular vote 33,658 22,210 8,814
Percentage 52.04% 34.34% 13.63%

Wisconsin president election results 1852.svg
County Results:


Pierce:      30-40%      40-50%      50-60%      60-70%      80-90%
Scott:      40-50%      50-60%
Hale:      30-40%      40-50%



President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Wisconsin was held on November 2, 1852. Wisconsin voters chose five electors to the Electoral College, who voted for President and Vice President.

Democratic Party candidate Franklin Pierce won the state with 52% of the popular vote, winning Wisconsin's five electoral votes.[1]

Results[edit]

United States presidential election in Wisconsin, 1852
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William Rufus DeVane King of Alabama 33,658 52.04% 5 100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 22,210 34.34% 0 0.00%
Free Soil John Parker Hale of New Hampshire George Washington Julian of Indiana 8,814 13.63% 0 0.00%
Total 64,682 100.00% 5 100.00%


References[edit]

  1. ^ "1852 Presidential General Election Results - Wisconsin". Retrieved August 17, 2016.