1856 United States presidential election in Alabama

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← 1852 November 2, 1852 1860 →
  Hon. James Buchanan - NARA - 528318-crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 9 0
Popular vote 46,739 28,552
Percentage 62.08% 37.92%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Alabama was held on November 4, 1856. Alabama voters chose 9 electors to represent the state in the Electoral College, which chose the president and vice president.

Alabama was won by Senator James Buchanan (DPennsylvania), running with Representative and future presidential candidate in the 1860 presidential election John C. Breckinridge, with 62.08% of the popular vote, against the 13th president of the United States Millard Fillmore (ANew York), running with the 2nd United States Ambassador to Germany Andrew Jackson Donelson, with 37.92% of the popular vote[1].

The Republican Party nominee John C. Frémont was not on the ballot.


United States presidential election in Alabama, 1856
Party Candidate Votes %
Democratic James Buchanan 46,739 62.08%
Know Nothing Millard Fillmore 28,552 37.92%
Total votes 75,291 100%


  1. ^ "1856 Presidential Election Results Alabama".