1856 United States presidential election in Arkansas

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← 1852 November 2, 1852 1860 →
  Hon. James Buchanan - NARA - 528318-crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 4 0
Popular vote 21,910 10,732
Percentage 67.12% 32.88%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Arkansas was held on November 4, 1856. Arkansas voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

Arkansas voted for the Democratic nominee James Buchanan, who received 67% of the vote.[1]

Republican Party nominee John C. Frémont was not on the ballot.


United States presidential election in Arkansas, 1856
Party Candidate Votes %
Democratic James Buchanan 21,910 67.12%
Know Nothing Millard Fillmore 10,732 32.88%
Total votes 32,642 100%


  1. ^ "1856 Presidential General Election Results - Arkansas". David Leip's U.S. Election Atlas. Retrieved 2017-06-05.