1856 United States presidential election in Florida

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United States presidential election in Florida, 1856

← 1852 November 4, 1856 1860 →
  Hon. James Buchanan - NARA - 528318-crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 3 0
Popular vote 6,358 4,833
Percentage 56.81% 43.19%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Florida took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Florida voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Florida by a margin of 13.62%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results[edit]

United States presidential election in Florida, 1856[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 6,358 56.81% 3 100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 4,833 43.19% 0 0.00%
Total 11,191 100.00% 3 100.00%

References[edit]

  1. ^ "1856 Presidential General Election Results - Florida". U.S. Election Atlas. Retrieved 2 December 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.