1856 United States presidential election in Maryland

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United States presidential election in Maryland, 1856

← 1852 November 4, 1856 1860 →
  Millard Fillmore by Brady Studio 1855-65-crop.jpg Hon. James Buchanan - NARA - 528318-crop.jpg
Nominee Millard Fillmore James Buchanan
Party Know Nothing Democratic
Home state New York Pennsylvania
Running mate Andrew Jackson Donelson John C. Breckinridge
Electoral vote 8 0
Popular vote 47,452 39,123
Percentage 54.63% 45.04%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Maryland took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland voted for the Know Nothing candidate, former president Millard Fillmore, over the Democratic candidate, James Buchanan, and Republican candidate, John C. Frémont.

Fillmore won the state by a margin of 9.59%. Maryland became the only state to vote for Fillmore during the election.


United States presidential election in Maryland, 1856[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 47,452 54.63% 8 100.00%
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 39,123 45.04% 0 0.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 285 0.33% 0 0.00%
Total 86,860 100.00% 8 100.00%


  1. ^ "1856 Presidential General Election Results - Maryland".