1860 United States presidential election in Connecticut

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1860 United States presidential election in Connecticut

← 1856 November 2, 1860 1864 →
  Abraham Lincoln O-26 by Hesler, 1860 (cropped).jpg BradyHandy-StephenADouglas restored.jpg John C Breckinridge-04775-restored.jpg
Nominee Abraham Lincoln Stephen A. Douglas John C. Breckinridge
Party Republican Democratic Southern Democratic
Home state Illinois Illinois Kentucky
Running mate Hannibal Hamlin Herschel Vespasian Johnson Joseph Lane
Electoral vote 6 0 0
Popular vote 43,486 17,364 16,558
Percentage 53.86% 21.50% 20.51%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Connecticut took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose six electors of the Electoral College, who voted for president and vice president.

Connecticut was won by Republican candidate Abraham Lincoln, who won by a margin of 32.36%.

Results[edit]

1860 United States presidential election in Connecticut[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 43,486 53.86% 6 100.00%
Democratic Stephen A. Douglas of Illinois Herschel Vespasian Johnson of Georgia 17,364 21.50% 0 0.00%
Southern Democratic John C. Breckinridge of Kentucky Joseph Lane of Oregon 16,558 20.51% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 3,337 4.13% 0 0.00%
Total 80,745 100.00% 6 100.00%

References[edit]

  1. ^ "1860 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 24 December 2013.