1860 United States presidential election in Oregon

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United States presidential election in Oregon, 1860

November 6, 1860 1864 →
  Abraham Lincoln O-26 by Hesler, 1860 (cropped).jpg John C Breckinridge-04775-restored.jpg BradyHandy-StephenADouglas restored.jpg
Nominee Abraham Lincoln John C. Breckinridge Stephen A. Douglas
Party Republican Southern Democratic Democratic
Home state Illinois Kentucky Illinois
Running mate Hannibal Hamlin Joseph Lane Herschel V. Johnson
Electoral vote 3 0 0
Popular vote 5,344 5,074 4,131
Percentage 36.20% 34.37% 27.99%

President before election

James Buchanan

Elected President

Abraham Lincoln

The 1860 United States presidential election in Oregon took place on November 6, 1860, as part of the 1860 United States presidential election. Oregon voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Oregon was won by Illinois Representative Abraham Lincoln (RKentucky), running with Senator Hannibal Hamlin, with 36.20% of the popular vote, against the 14th Vice President of the United States John C. Breckinridge (SDKentucky), running with Senator Joseph Lane, with 34.37% of the popular vote and Senator Stephen A. Douglas (DIllinois), running with 41st Governor of Georgia Herschel V. Johnson, with 27.99% of the popular vote.


United States presidential election in Oregon, 1860[1]
Party Candidate Votes %
Republican Abraham Lincoln 5,344 36.20%
Southern Democratic John C. Breckinridge 5,074 34.37%
Democratic Stephen A. Douglas 4,131 27.99%
Constitutional Union John Bell 212 1.44%
Total votes 14,761 100%


  1. ^ "1860 Presidential Election Results Oregon".