1868 New Jersey gubernatorial election

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
New Jersey gubernatorial election, 1868

← 1865 November 3, 1868 1871 →
  Theodore Fitz Randolph - Brady-Handy.jpg John Insley Blair.jpg
Nominee Theodore Fitz Randolph John Insley Blair
Party Democratic Republican
Popular vote 83,955 79,333
Percentage 51.42% 48.59%

Governor before election

Marcus Lawrence Ward
Republican

Elected Governor

Theodore Fitz Randolph
Democratic

The 1868 New Jersey gubernatorial election was held on November 3, 1868. Democratic nominee Theodore Fitz Randolph defeated Republican nominee John Insley Blair with 51.42% of the vote.

General election[edit]

Candidates[edit]

Major party candidates

  • Theodore Fitz Randolph, Democratic
  • John Insley Blair, Republican

Results[edit]

New Jersey gubernatorial election, 1868[1]
Party Candidate Votes % ±
Democratic Theodore Fitz Randolph 83,955 51.42%
Republican John Insley Blair 79,333 48.59%
Majority
Turnout
Democratic hold Swing

References[edit]

  1. ^ "Guide to U.S. Elections". Books.google.com. Retrieved 2016-01-25.