1870 Vermont gubernatorial election

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Vermont gubernatorial election, 1870

← 1869 September 6, 1870 (1870-09-06) 1872 →
  John Wolcott Stewart.jpg Homer W. Heaton Vermont politician.jpg
Candidate John W. Stewart Homer W. Heaton
Party Republican Democratic
Popular vote 33,367 12,058
Percentage 73.4% 26.5%

Governor before election

George W. Hendee
Republican

Elected Governor

John W. Stewart
Republican

The Vermont gubernatorial election of 1870 took place on September 6, 1870. Incumbent Republican George W. Hendee, per the "Mountain Rule",[1] did not run for re-election to a full term as Governor of Vermont. Republican candidate John W. Stewart defeated Democratic candidate Homer W. Heaton to succeed him. The 1870 election marked the start of biennial gubernatorial elections in Vermont.

Results[edit]

Vermont gubernatorial election, 1870[2]
Party Candidate Votes % ±
Republican John W. Stewart 33,367 73.4 -0.1
Democratic Homer W. Heaton 12,058 26.5 +0.1
N/A Other 4 0.0 -0.1
Total votes 45,429 100

References[edit]

  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 4 October 2015.
  2. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 4 October 2015.