1880 United States presidential election in Minnesota

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United States presidential election in Minnesota, 1880

← 1876 November 2, 1880 1884 →
  JamesGarfield.png WinfieldScottHancock.png
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 5 0
Popular vote 93,902 53,315
Percentage 62.28% 35.36%

MNPresidential1880.svg

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in Minnesota took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Minnesota voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 30.25%.

With 62.28% of the popular vote, Minnesota would be Garfield's third strongest victory in terms of percentage in the popular vote after Vermont and Nebraska.[1]

Results[edit]

United States presidential election in Minnesota, 1880[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 93,902 62.87% 3 100.00%
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 53,315 35.36% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 3,267 2.17% 0 0.00%
Prohibition Neal Dow of Maine Henry Adams Thompson of Ohio 286 0.19% 0 0.00%
Total 150,770 100.00% 5 100.00%

References[edit]

  1. ^ "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1880 Presidential General Election Results - Minnesota".