1884 United States presidential election in Maine

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
United States presidential election in Maine, 1884
Flag of Maine (1901–1909).svg
← 1880 November 4, 1884 1888 →
  JamesGBlaine.png StephenGroverCleveland.png
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 4 0
Popular vote 72,217 52,153
Percentage 55.34% 39.97%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Maine took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Maine voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 15.37%.

Results[edit]

United States presidential election in Maine, 1884[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 72,217 55.34% 6 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 52,153 39.97% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 3,955 3.03% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 2,160 1.65% 0 0.00%
N/A Others Others 6 0.01% 0 0.00%
Total 130,491 100.00% 6 100.00%

References[edit]

  1. ^ "1884 Presidential General Election Results - Maine".