1884 United States presidential election in New Hampshire

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1884 United States presidential election in New Hampshire

← 1880 November 4, 1884 1888 →
  JamesGBlaine.png StephenGroverCleveland.png
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 4 0
Popular vote 43,254 39,198
Percentage 51.14% 46.34%

United States presidential election in New Hampshire, 1884 results by county.svg
Results by county

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in New Hampshire took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

New Hampshire voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 4.80%.

Results[edit]

1884 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 43,254 51.14% 4 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 39,198 46.34% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 1,580 1.87% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 554 0.65% 0 0.00%
Total 84,586 100.00% 4 100.00%

References[edit]

  1. ^ "1884 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.