1884 United States presidential election in South Carolina

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
United States presidential election in South Carolina, 1884

← 1880 November 4, 1884 1888 →
  Grover Cleveland - NARA - 518139 (cropped).jpg James G. Blaine - Brady-Handy.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 9 0
Popular vote 69,845 21,730
Percentage 75.25% 23.41%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in South Carolina took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

South Carolina voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a wide margin of 51.84%.

Results[edit]

United States presidential election in South Carolina, 1884[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 69,845 75.25% 9 100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 21,730 23.41% 0 0.00%
N/A Others Others 1,237 1.33% 0 0.00%
Total 92,812 100.00% 9 100.00%

References[edit]

  1. ^ "1884 Presidential General Election Results - South Carolina". U.S. Election Atlas. Retrieved 23 December 2013.