1884 United States presidential election in Virginia

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United States presidential election in Virginia, 1884

← 1880 November 4, 1884 1888 →
  1882, Sarony, Napoleon, (Stephen) Grover Cleveland.jpg James G. Blaine - Brady-Handy.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 12 0
Popular vote 145,491 139,356
Percentage 51.05% 48.90%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Virginia took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for president and vice president.

Virginia voted for the Democratic candidate, New York Governor Grover Cleveland over the Republican candidate, former Secretary of State James G. Blaine. Cleveland won Virginia by a margin of 2.15%.

Results[edit]

United States presidential election in Virginia, 1884[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 145,491 51.05% 12
Republican James G. Blaine 139,356 48.90% 0
Prohibition John St. John 130 0.05% 0
Totals 284,977 100.0% 12

References[edit]

  1. ^ "1884 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.