1888 United States presidential election in Colorado

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United States presidential election in Colorado, 1888

← 1884 November 6, 1888 1892 →
  Pach Brothers - Benjamin Harrison.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 3 0
Popular vote 50,772 37,549
Percentage 55.22% 40.84%

President before election

Grover Cleveland

Elected President

Benjamin Harrison

The 1888 United States presidential election in Colorado took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Colorado voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 14.38 percent.

With 55.22% of the popular vote, Colorado would prove to be Harrison's fifth strongest victory in terms of percentage in the popular vote after Vermont, Nevada, Maine and Kansas.[1]


United States presidential election in Colorado, 1888[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 50,772 55.22% 3 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 37,549 40.84% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 2,182 2.37% 0 0.00%
Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 1,266 1.38% 0 0.00%
N/A Others Others 177 0.19% 0 0.00%
Total 91,946 100.00% 3 100.00%


  1. ^ "1888 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1888 Presidential General Election Results - Colorado". U.S. Election Atlas. Retrieved 23 December 2013.