1890 United States elections

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1890 United States elections
Midterm elections
Election dayNovember 4
Incumbent presidentBenjamin Harrison (Republican)
Next Congress52nd
Senate elections
Overall controlRepublican Hold
Seats contested28 of 85 seats[1]
Net seat changeDemocratic +2[2]
House elections
Overall controlDemocratic Gain
Seats contestedAll 332 voting seats
Net seat changeDemocratic +86[2]
House052ElectionMap.png
1890 House of Representatives election results

  Democratic seat
  Republican seat
  Independent seat

The 1890 United States elections occurred in the middle of Republican President Benjamin Harrison's term. Members of the 52nd United States Congress were chosen in this election. The Republicans suffered major losses due to the Panic of 1890 and the unpopularity of the McKinley Tariff. The Populist Party also emerged as an important third party.

Republicans suffered massive losses to Democrats in the House, and the Democrats took control of the chamber.[3]

In the Senate, Democrats made minor gains, but Republicans kept control of the chamber. The Populists joined the Senate for the first time, electing two Senators.[4]

See also[edit]

References[edit]

  1. ^ Not counting special elections.
  2. ^ a b Congressional seat gain figures only reflect the results of the regularly-scheduled elections, and do not take special elections into account.
  3. ^ "Party Divisions of the House of Representatives". United States House of Representatives. Retrieved 25 June 2014.
  4. ^ "Party Division in the Senate, 1789-Present". United States Senate. Retrieved 25 June 2014.