1892 United States presidential election in Iowa

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United States presidential election in Iowa, 1892

← 1888 November 8, 1892 1896 →
  Benjamin Harrison, head and shoulders bw photo, 1896.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson I
Electoral vote 13 0
Popular vote 219,795 196,367
Percentage 49.60% 44.31%

President before election

Benjamin Harrison

Elected President

Grover Cleveland

The 1892 United States presidential election in Iowa took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Iowa voters chose thirteen electors to the Electoral College, which selected the president and vice president.

Iowa was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.


United States presidential election in Iowa, 1892[1]
Party Candidate Votes Percentage Electoral votes
Republican Benjamin Harrison (incumbent) 219,795 49.60% 13
Democratic Grover Cleveland 196,367 44.31% 0
People's James Weaver 20,595 4.65% 0
Prohibition John Bidwell 6,402 1.44% 0
Totals 443,159 100.00% 13
Voter turnout


  1. ^ Dave Leip’s U.S. Election Atlas; https://uselectionatlas.org/RESULTS/state.php?fips=19&year=1892&f=0&off=0&elect=0 Presidential General Election Results – Iowa]