1892 United States presidential election in Maryland

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United States presidential election in Maryland, 1892

← 1888 November 8, 1892 1896 →
  StephenGroverCleveland.png Benjamin Harrison, head and shoulders bw photo, 1896.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote 8 0
Popular vote 113,866 92,736
Percentage 53.39% 43.48%

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Maryland took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Maryland voters chose eight electors to the Electoral College, which selected the president and vice president.

Maryland was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Results[edit]

United States presidential election in Maryland, 1892[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 113,866 53.39% 8
Republican Benjamin Harrison (incumbent) 92,736 43.48% 0
Prohibition John Bidwell 5,877 2.76% 0
People's James Weaver 796 0.37% 0
Totals 213,275 100.00% 8
Voter turnout

References[edit]

  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Maryland

Notes[edit]