1892 United States presidential election in Minnesota

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United States presidential election in Minnesota, 1892

← 1888 November 8, 1892 1896 →
  Benjamin Harrison, head and shoulders bw photo, 1896.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson I
Electoral vote 9 0
Popular vote 122,823 100,920
Percentage 45.96% 37.76%

  James B. Weaver 1892.jpg JohnBidwell.png
Nominee James B. Weaver John Bidwell
Party Populist Prohibition
Home state Iowa California
Running mate James G. Field James Cranfill
Electoral vote 0 0
Popular vote 29,313 14,182
Percentage 10.97% 5.31%

MNPresidential1892.svg

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Minnesota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

Minnesota was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Minnesota was the state where Bidwell performed the best and the only one where he broke 5%.

Results[edit]

United States presidential election in Minnesota, 1892[1]
Party Candidate Votes Percentage Electoral votes
Republican Benjamin Harrison (incumbent) 122,823 45.96% 9
Democratic Grover Cleveland 100,920 37.76% 0
People's James Weaver 29,313 10.97% 0
Prohibition John Bidwell 14,182 5.31% 0
Totals 267,238 100.00% 9
Voter turnout

References[edit]

  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Minnesota

Notes[edit]