1892 United States presidential election in New Jersey
|Elections in New Jersey|
The 1892 United States presidential election in New Jersey took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.
New Jersey voted for the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term, over Republican nominee, incumbent President Benjamin Harrison. Cleveland won his birth state by a narrow margin of 4.43%.
|United States presidential election in New Jersey, 1892|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Democratic||Grover Cleveland of New York||Adlai Ewing Stevenson I of Illinois||171,066||50.67%||10||100.00%|
|Republican||Benjamin Harrison of Indiana||Whitelaw Reid of New York||156,101||46.24%||0||0.00%|
|Prohibition||John Bidwell of California||James Cranfill of Texas||8,134||2.41%||0||0.00%|
|Socialist Labor||Simon Wing of Massachusetts||Charles Matchett of New York||1,337||0.40%||0||0.00%|
|People's||James Baird Weaver of Iowa||James Gaven Field of Virginia||985||0.29%||0||0.00%|
- "1892 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved 23 December 2013.
|This New Jersey elections-related article is a stub. You can help Wikipedia by expanding it.|