1896 United States presidential election in Minnesota

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United States presidential election in Minnesota, 1896

← 1892 November 3, 1896 1900 →
  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 9 0
Popular vote 193,503 139,735
Percentage 53.77% 40.89%

MNPresidential1896.svg

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Minnesota took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

Minnesota was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.

Results[edit]

United States presidential election in Minnesota, 1896[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 193,503 53.77% 9
Democratic William Jennings Bryan 139,735 40.89% 0
Prohibition Joshua Levering 4,348 1.27% 0
National Democratic John M. Palmer 3,222 0.94% 0
Socialist Labor Charles Matchett 954 0.28% 0
Totals 341,762 100.00% 9
Voter turnout

References[edit]

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota

Notes[edit]