1896 United States presidential election in New Hampshire

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1896 United States presidential election in New Hampshire

← 1892 November 3, 1896 1900 →
  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 4 0
Popular vote 57,444 21,650
Percentage 68.66% 25.88%

President before election

Grover Cleveland

Elected President

William McKinley

The 1896 United States presidential election in New Hampshire took place on November 3, 1896 as part of the 1896 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

New Hampshire overwhelmingly voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a margin of 42.78%.

With 68.66% of the popular vote, New Hampshire would be McKinley's third strongest victory in terms of percentage in the popular vote after neighboring Vermont and Massachusetts.[1] The state was also the best performance for National Democratic Party candidate John M. Palmer, who won 4.21% of the vote.

Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers in the 1896 election, but held little-to-no appeal in the Northeastern states like New Hampshire.


1896 United States presidential election in New Hampshire[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William McKinley of Ohio Garret Hobart of New Jersey 57,444 68.66% 4 100.00%
Democratic William Jennings Bryan of Nebraska Arthur Sewall of Maine 21,650 25.88% 0 0.00%
National Democratic John McAuley Palmer of Illinois Simon Bolivar Buckner of Kentucky 3,520 4.21% 0 0.00%
Prohibition Joshua Levering of Maryland Hale Johnson of Illinois 779 0.93% 0 0.00%
Socialist Labor Charles Horatio Matchett of New York Matthew Maguire of New Jersey 228 0.27% 0 0.00%
Prohibition Charles Eugene Bentley of Nebraska James Haywood Southgate of North Carolina 49 0.06% 0 0.00%
Total 83,670 100.00% 4 100.00%


  1. ^ "1896 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1896 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.