1896 United States presidential election in Texas

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United States presidential election in Texas, 1896

← 1892 November 3, 1896 1900 →
  William Jennings Bryan (1860-1925) (10506717125).jpg William McKinley by Courtney Art Studio, 1896.jpg
Nominee William J. Bryan William McKinley
Party Democratic Republican
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 15 0
Popular vote 370,434 167,520
Percentage 68.0% 30.8%

President before election

Grover Cleveland

Elected President

William McKinley

The 1896 United States presidential election in Texas took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Texas voters chose fifteen electors to the Electoral College, which selected the president and vice president.

Texas was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Four electors cast their Vice Presidential ballots for Thomas E. Watson.


United States presidential election in Texas, 1896[1]
Party Candidate Votes Percentage Electoral votes
Democratic William Jennings Bryan 370,434 68.00% 15
Republican William McKinley 167,520 30.75% 0
National Democratic John M. Palmer 5,046 0.93% 0
Prohibition Joshua Levering 1,786 0.33% 0
Totals 544,786 100.00% 15
Voter turnout


  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Texas