1900 United States presidential election in Minnesota

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United States presidential election in Minnesota, 1900

← 1896 November 6, 1900 1904 →
  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 9 0
Popular vote 190,461 112,901
Percentage 60.21% 35.69%


President before election

William McKinley

Elected President

William McKinley

The 1900 United States presidential election in Minnesota took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

Minnesota was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. The ticket won the state by a margin of 24.52 percent.

With 60.21% of the popular vote, Minnesota would be McKinley's fifth strongest victory in terms of percentage in the popular vote after Vermont, North Dakota, Maine and Pennsylvania.[1]


United States presidential election in Minnesota, 1900[2]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 190,461 60.21% 9
Democratic William Jennings Bryan 112,901 35.69% 0
Prohibition John Woolley 8,555 2.70% 0
Social Democratic Eugene Debs 3,065 0.97% 0
Socialist Labor Joseph Maloney 1,329 0.42% 0
Totals 316,311 100.00% 9
Voter turnout


  1. ^ "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota