1900 United States presidential election in North Dakota

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United States presidential election in North Dakota, 1900

← 1896 November 6, 1900 1904 →
  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 3 0
Popular vote 35,898 20,531
Percentage 62.12% 35.53%

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in North Dakota took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. North Dakota voters chose three electors to the Electoral College, which selected the president and vice president.

North Dakota was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. McKinley won the state but a margin of 26.59%.

With 62.12% of the popular vote, North Dakota would be McKinley's second strongest victory in terms of percentage in the popular vote after Vermont[1].

Results[edit]

United States presidential election in North Dakota, 1900[2]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 35,898 62.12% 3
Democratic William Jennings Bryan 20,531 35.53% 0
Prohibition John Woolley 731 1.26% 0
Social Democratic Eugene Debs 520 0.90% 0
Populist Wharton Barker 111 0.19% 0
Totals 57,791 100.00% 3
Voter turnout

References[edit]

  1. ^ "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – North Dakota

Notes[edit]