1904 United States presidential election in Connecticut

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United States presidential election in Connecticut, 1904

← 1900 November 8, 1904 1908 →
  President Theodore Roosevelt, 1904.jpg AltonBParker.png
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 7 0
Popular vote 111,089 72,909
Percentage 58.12% 38.15%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in Connecticut took place on November 8, 1904 as part of the 1904 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut overwhelmingly voted for the Republican nominee, President Theodore Roosevelt, over the Democratic nominee, former Chief Judge of New York Court of Appeals Alton B. Parker. Roosevelt won Connecticut by a margin of 19.97%.

Results[edit]

United States presidential election in Connecticut, 1904[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Theodore Roosevelt of New York Charles Warren Fairbanks of Indiana 111,089 58.12% 7 100.00%
Democratic Alton Brooks Parker of New York Henry Gassaway Davis of West Virginia 72,909 38.15% 0 0.00%
Socialist Eugene Victor Debs of Indiana Benjamin Hanford of New York 4,543 2.38% 0 0.00%
Prohibition Silas Comfort Swallow of Pennsylvania George Washington Carroll of Texas 1,506 0.79% 0 0.00%
Socialist Labor Charles Hunter Corregan of New York William Wesley Cox of Illinois 575 0.30% 0 0.00%
People's Thomas Edward Watson of Georgia Thomas Tibbles of Nebraska 495 0.26% 0 0.00%
N/A Others Others 11 0.01% 0 0.00%
Total 191,128 100.00% 7 100.00%

References[edit]

  1. ^ "1904 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 23 December 2013.