1904 United States presidential election in Idaho

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United States presidential election in Idaho, 1904

← 1900 November 8, 1904 1908 →
  President Roosevelt - Pach Bros.tif AltonBParker.png EugeneVictorDebs.png
Nominee Theodore Roosevelt Alton B. Parker Eugene V. Debs
Party Republican Democratic Socialist
Home state New York New York Indiana
Running mate Charles W. Fairbanks Henry G. Davis Benjamin Hanford
Electoral vote 3 0 0
Popular vote 47,783 18,480 4,949
Percentage 65.84% 25.46% 6.82%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in Idaho took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Idaho voters chose three electors to the Electoral College, which selected the president and vice president.

Idaho was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana.

Results[edit]

United States presidential election in Idaho, 1904[1]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt 47,783 65.84% 3
Democratic Alton B. Parker 18,480 25.46% 0
Social Democratic Eugene Debs 4,949 6.82% 0
Prohibition Silas C. Swallow 1,013 1.40% 0
Populist Thomas E. Watson 353 0.49% 0
Totals 72,578 100.00% 3
Voter turnout

References[edit]

  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Idaho

Notes[edit]