1904 United States presidential election in North Dakota

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United States presidential election in North Dakota, 1904

← 1900 November 8, 1904 1908 →
  President Roosevelt - Pach Bros.tif AltonBParker.png
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 4 0
Popular vote 52,595 14,273
Percentage 75.12% 20.39%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in North Dakota took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. North Dakota voters chose four electors to the Electoral College, which selected the president and vice president.

North Dakota was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. The ticket won the state by a margin of 54.73 percent.

With 75.12% of the popular vote, North Dakota would be Roosevelt's second strongest victory in terms of percentage in the popular vote after Vermont.[1]

Results[edit]

United States presidential election in North Dakota, 1904[2]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt 52,595 75.12% 4
Democratic Alton B. Parker 14,273 20.39% 0
Social Democratic Eugene Debs 2,009 2.87% 0
Prohibition Silas C. Swallow 1,137 1.62% 0
Totals 70,014 100.00% 4
Voter turnout

References[edit]

  1. ^ "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – North Dakota

Notes[edit]