1908 United States presidential election in North Dakota

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United States presidential election in North Dakota, 1908

← 1904 November 3, 1908 1912 →
  William Howard Taft.jpg WilliamJBryan1902.png
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John Worth Kern
Electoral vote 4 0
Popular vote 57,680 32,885
Percentage 61.02% 34.79%

President before election

Theodore Roosevelt

Elected President

William Howard Taft

The 1908 United States presidential election in North Dakota took place on November 3, 1908. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

North Dakota voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a margin of 26.23%.

With 61.02% of the popular vote, North Dakota would be Taft's fourth strongest victory in terms of percentage in the popular vote after Vermont, Maine and Michigan.[1]


United States presidential election in North Dakota, 1908[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William Howard Taft of Ohio James Schoolcraft Sherman of New York 57,680 61.02% 4 100.00%
Democratic William Jennings Bryan of Nebraska John Worth Kern of Indiana 32,885 34.79% 0 0.00%
Socialist Eugene Victor Debs of Indiana Benjamin Hanford of New York 2,421 2.56% 0 0.00%
Prohibition Eugene Wilder Chafin of Illinois Aaron Sherman Watkins of Ohio 1,496 1.58% 0 0.00%
Independence Thomas Louis Hisgen of Massachusetts John Temple Graves of Georgia 43 0.05% 0 0.00%
Total 94,525 100.00% 4 100.00%


  1. ^ "1908 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1908 Presidential General Election Results - North Dakota". U.S. Election Atlas. Retrieved 23 December 2013.