1912 United States presidential election in South Carolina

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United States presidential election in South Carolina, 1912

← 1908 November 5, 1912 1916 →
  Woodrow Wilson-H&E.jpg Theodore Roosevelt-Pach.jpg
Nominee Woodrow Wilson Theodore Roosevelt
Party Democratic Progressive
Home state New Jersey New York
Running mate Thomas R. Marshall Hiram Johnson
Electoral vote 9 0
Popular vote 48,357 1,293
Percentage 95.94% 2.57%

President before election

William Howard Taft

Elected President

Woodrow Wilson

The 1912 United States presidential election in South Carolina took place on November 5, 1912, as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

South Carolina was won by the Democratic nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall. Wilson and Marshall defeated incumbent President William Howard Taft, and his running mate Vice President James S. Sherman and Progressive Party candidates, former President Theodore Roosevelt and his running mate California Governor Hiram Johnson.

Wilson won South Carolina by a landslide margin of 93.37 percent.


United States presidential election in South Carolina, 1912[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Woodrow Wilson of New Jersey Thomas Riley Marshall of Indiana 48,357 95.94% 9 100.00%
Progressive Theodore Roosevelt of New York Hiram Warren Johnson of California 1,293 2.57% 0 0.00%
Republican William Howard Taft of Ohio Nicholas Murray Butler of New York 536 1.06% 0 0.00%
Socialist Eugene Victor Debs of Indiana Emil Seidel of Wisconsin 164 0.33% 0 0.00%
N/A Others Others 55 0.11% 0 0.00%
Total 50,405 100.00% 9 100.00%


  1. ^ "1912 Presidential General Election Results - South Carolina". U.S. Election Atlas. Retrieved 23 December 2013.