1940 United States presidential election in Nevada

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United States presidential election in Nevada, 1940

← 1936 November 5, 1940[1] 1944 →

All 3 Nevada votes to the Electoral College
  FDRoosevelt1938.png WendellWillkie.jpg
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York Indiana
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 3 0
Popular vote 31,945 21,229
Percentage 60.1% 39.9%

President before election

Franklin D. Roosevelt

Elected President

Franklin D. Roosevelt

The 1940 United States presidential election in Nevada took place on November 5, 1940, as part of the 1940 United States presidential election. Nevada voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Nevada was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 60.08% of the popular vote, against Wendell Willkie (RIndiana), running with Minority Leader Charles L. McNary, with 39.92% of the popular vote.[3][4] As of the 2016 presidential election, this is the last election in which Lyon County and Churchill County voted for a Democratic presidential candidate.[5]


United States presidential election in Nevada, 1940
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 31,945 60.08%
Republican Wendell Willkie 21,229 39.92%
Total votes 53,174 100%


  1. ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 21, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 21, 2018.
  3. ^ "1940 Presidential General Election Results - Nevada". Retrieved August 21, 2018.
  4. ^ "The American Presidency Project - Election of 1940". Retrieved August 21, 2018.
  5. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016