1944 United States presidential election in Iowa

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United States presidential election in Iowa, 1944

← 1940 November 7, 1944[1] 1948 →

All 10 Iowa votes to the Electoral College
  ThomasDewey.png 1944 portrait of FDR (1)(small).jpg
Nominee Thomas E. Dewey Franklin D. Roosevelt
Party Republican Democratic
Home state New York New York
Running mate John W. Bricker Harry S. Truman
Electoral vote 10 0
Popular vote 547,267 499,876
Percentage 51.9% 47.5%

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1944 United States presidential election in Iowa took place on November 7, 1944, as part of the 1944 United States presidential election. Iowa voters chose ten[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Iowa was won by Governor Thomas E. Dewey (RNew York), running with Governor John Bricker, with 51.99% of the popular vote, against incumbent President Franklin D. Roosevelt (DNew York), running with Senator Harry S. Truman, with 47.49% of the popular vote.[3][4]

Results[edit]

United States presidential election in Iowa, 1944
Party Candidate Votes %
Republican Thomas E. Dewey 547,267 51.99%
Democratic Franklin D. Roosevelt (inc.) 499,876 47.49%
Prohibition Claude A. Watson 3,752 0.36%
Write-in 1,704 0.16%
Total votes 1,052,599 100%

References[edit]

  1. ^ "United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 22, 2017.
  2. ^ "1944 Election for the Fortieth Term (1945-49)". Retrieved December 22, 2017.
  3. ^ "1944 Presidential General Election Results - Iowa". Retrieved December 22, 2017.
  4. ^ "The American Presidency Project - Election of 1944". Retrieved December 22, 2017.