1944 United States presidential election in Nevada

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United States presidential election in Nevada, 1944

← 1940 November 7, 1944[1] 1948 →

All 3 Nevada votes to the Electoral College
  1944 portrait of FDR (1)(small).jpg ThomasDewey.png
Nominee Franklin D. Roosevelt Thomas E. Dewey
Party Democratic Republican
Home state New York New York
Running mate Harry S. Truman John W. Bricker
Electoral vote 3 0
Popular vote 29,623 24,611
Percentage 54.6% 45.4%

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1944 United States presidential election in Nevada took place on November 7, 1944, as part of the 1944 United States presidential election. Nevada voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Nevada was won by incumbent President Franklin D. Roosevelt (DNew York), running with Senator Harry S. Truman, with 54.62% of the popular vote, against Governor Thomas E. Dewey (RNew York), running with Governor John W. Bricker, with 45.38% of the popular vote.[3][4]

Results[edit]

United States presidential election in Nevada, 1944
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 29,623 54.62%
Republican Thomas E. Dewey 24,611 45.38%
Total votes 54,234 100%

References[edit]

  1. ^ "United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 26, 2017.
  2. ^ "1944 Election for the Fortieth Term (1945-49)". Retrieved December 26, 2017.
  3. ^ "1944 Presidential General Election Results - Nevada". Retrieved December 26, 2017.
  4. ^ "The American Presidency Project - Election of 1944". Retrieved December 26, 2017.