1948 United States presidential election in Kentucky

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United States presidential election in Kentucky, 1948

← 1944 November 2, 1948[1] 1952 →

All 11 Kentucky votes to the Electoral College
  Harry S. Truman.jpg ThomasDewey.png
Nominee Harry S. Truman Thomas Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 11 0
Popular vote 466,756 341,210
Percentage 56.7% 41.5%

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Kentucky took place on November 2, 1948, as part of the 1948 United States presidential election. Kentucky voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Kentucky was won by incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 56.74% of the popular vote, against Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 41.48% of the popular vote.[3][4]

Results[edit]

United States presidential election in Kentucky, 1948
Party Candidate Votes %
Democratic Harry S. Truman (inc.) 466,756 56.74%
Republican Thomas Dewey 341,210 41.48%
Dixiecrat Strom Thurmond 10,411 1.27%
Write-in 4,281 0.52%
Total votes 822,658 100%

References[edit]

  1. ^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 30, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 30, 2017.
  3. ^ "1948 Presidential General Election Results - Kentucky". Retrieved October 30, 2017.
  4. ^ "The American Presidency Project - Election of 1948". Retrieved October 30, 2017.