1988 United States presidential election in Louisiana

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United States presidential election in Louisiana, 1988

← 1984 November 8, 1988 1992 →
  1988 Bush.jpg 1988 Dukakis.jpg
Nominee George H.W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 10 0
Popular vote 883,702 717,460
Percentage 54.27% 44.06%

Parish Results

President before election

Ronald Reagan

Elected President

George H.W. Bush

The 1988 United States presidential election in Louisiana took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.

Louisiana strongly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. The margin was ten percent, which was nonetheless the best Southern state showing for Dukakis. As of the 2016 presidential election, this is the last election in which Tensas Parish voted for a Republican presidential candidate.[1]


United States presidential election in Louisiana, 1988[2]
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush 883,702 54.27% 10
Democratic Michael Dukakis 717,460 44.06% 0
America First David Duke 18,612 1.14% 0
Libertarian Ron Paul 4,115 0.25% 0
New Alliance Lenora Fulani 2,355 0.14% 0
Democrats for Economic Recovery Lyndon LaRouche 1,958 0.12% 0
Invalid or blank votes
Totals 1,628,202 100.00% 10
Voter turnout


  1. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
  2. ^ "1988 Presidential General Election Results – Louisiana". Dave Leip’s U.S. Election Atlas. Retrieved 2008-08-25.