1896 United States presidential election in Massachusetts
|Turnout||70.6% 4.0 pp|
|Elections in Massachusetts|
The 1896 United States presidential election in Massachusetts took place on November 3, 1896 as part of the 1896 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
Massachusetts overwhelmingly voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won Massachusetts by a margin of 43.15%.
|United States presidential election in Massachusetts, 1896|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||William McKinley of Ohio||Garret Hobart of New Jersey||278,976||69.47%||15||100.00%|
|Democratic||William Jennings Bryan of Nebraska||Arthur Sewall of Maine||105,711||26.32%||0||0.00%|
|National Democratic||John McAuley Palmer of Illinois||Simon Bolivar Buckner of Kentucky||11,749||2.93%||0||0.00%|
|Prohibition||Joshua Levering of Maryland||Hale Johnson of Illinois||2,998||0.75%||0||0.00%|
|Socialist Labor||Charles Horatio Matchett of New York||Matthew Maguire of New Jersey||2,114||0.53%||0||0.00%|
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1896 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1896 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
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