1884 United States presidential election in Rhode Island
|Elections in Rhode Island|
The 1884 United States presidential election in Rhode Island took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
|United States presidential election in Rhode Island, 1884|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||James Gillespie Blaine of Maine||John Alexander Logan of Illinois||19,030||58.07%||4||100.00%|
|Democratic||Grover Cleveland of New York||Thomas Andrews Hendricks of Indiana||12,391||37.81%||0||0.00%|
|Prohibition||John Pierce St. John of Kansas||William Daniel of Maryland||928||2.83%||0||0.00%|
|Greenback||Benjamin Franklin Butler of Massachusetts||Absolom Madden West of Mississippi||423||1.29%||0||0.00%|
- "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1884 Presidential General Election Results - Rhode Island".
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