1928 United States presidential election in Rhode Island

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United States presidential election in Rhode Island, 1928

← 1924 November 6, 1928 1932 →
  AlfredSmith.png Herbert Hoover - NARA - 532049.tif
Nominee Al Smith Herbert Hoover
Party Democratic Republican
Home state New York California
Running mate Joseph Taylor Robinson Charles Curtis
Electoral vote 5 0
Popular vote 118,973 117,522
Percentage 50.16% 49.55%

President before election

Calvin Coolidge

Elected President

Herbert Hoover

The 1928 United States presidential election in Rhode Island took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary forty-eight states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Democratic nominee, Governor Alfred E. Smith of New York, over the Republican nominee, Secretary of Commerce Herbert Hoover of California. Smith's running mate was Senator Joseph Taylor Robinson of Arkansas, while Hoover’s running mate was Senate Majority Leader Charles Curtis of Kansas.

Smith won Rhode Island by a very narrow margin of 0.61 percent, making him the first Democratic presidential candidate since Woodrow Wilson in 1912 to carry the state, and the first to win an absolute majority of the vote since Franklin Pierce in 1852 (Wilson won the state in 1912, but only with a 39.04% plurality). Although Hoover won more counties compares to Smith, key to Smith's victory were his appeal to Roman Catholic voters in Providence County and Bristol County.

1928 would mark the beginning of Rhode Island's transition from a strongly Yankee Republican state into a Democratic-leaning state. Since then, Republicans have only carried the state four times.

Rhode Island would not vote for another Republican presidential candidate until Dwight D. Eisenhower in 1952.


United States presidential election in Rhode Island, 1928[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Al Smith of Nebraska Joseph Taylor Robinson of Arkansas 118,973 50.16% 5 100.00%
Republican Herbert Hoover of California Charles Curtis of Kansas 117,522 49.55% 0 0.00%
Socialist Labor Verne L. Reynolds of Michigan Jeremiah D. Crowley of New York 416 0.18% 0 0.00%
Communist William Z. Foster of Massachusetts Benjamin Gitlow of New York 283 0.12% 0 0.00%
Total 237,194 100.00% 5 100.00%


  1. ^ "1928 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved 23 December 2013.