1916 Vermont gubernatorial election

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Vermont gubernatorial election, 1916

← 1914 November 7, 1916 (1916-11-07) 1918 →
  Horace French Graham.jpg No image.svg
Nominee Horace F. Graham William B. Mayo
Party Republican Democratic
Popular vote 43,265 15,789
Percentage 71.1% 25.9%

Governor before election

Charles W. Gates
Republican

Elected Governor

Horace F. Graham
Republican

The Vermont gubernatorial election of 1916 took place on November 7, 1916. Incumbent Republican Charles W. Gates, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace F. Graham defeated Democratic candidate William B. Mayo to succeed him.

Republican primary[edit]

Results[edit]

Republican primary results[2]
Party Candidate Votes % ±
Republican Horace F. Graham 33,244 99.9
Republican Other 37 0.1
Total votes 33,281 100

Democratic primary[edit]

Results[edit]

Democratic primary results[2]
Party Candidate Votes % ±
Democratic William B. Mayo 3,562 99.9
Democratic Other 1 0.0
Total votes 3,563 100

General election[edit]

Results[edit]

Vermont gubernatorial election, 1916[3]
Party Candidate Votes % ±
Republican Horace F. Graham 43,265 71.1
Democratic William B. Mayo 15,789 25.9
Socialist W. R. Rowland 920 1.5
Prohibition Lester W. Hanson 876 1.4
N/A Other 4 0.0
Total votes 60,854 100

References[edit]

  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
  2. ^ a b "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
  3. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.